When 3.00 g of NH3(g) (M = 17.03 g/mol) reacts with 18.0 g of HCl(g) (M = 36.46 g/mol), what is the theoretical yield of NH4Cl(s) in grams?
A
15.0 g
B
12.0 g
C
13.5 g
D
14.6 g
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1
First, write the balanced chemical equation for the reaction between NH3(g) and HCl(g) to form NH4Cl(s):
Calculate the number of moles of NH3(g) using its mass and molar mass:
Calculate the number of moles of HCl(g) using its mass and molar mass:
Determine the limiting reactant by comparing the mole ratio from the balanced equation. Since the reaction is 1:1, the reactant with fewer moles is the limiting reactant.
Calculate the theoretical yield of NH4Cl(s) in grams using the moles of the limiting reactant and the molar mass of NH4Cl(s):