Which of the following represents the correct electron configuration for a neutral atom of vanadium (atomic number 23)?
A
1s^2 2s^2 2p^6 3s^2 3p^6 3d^2 4s^3
B
1s^2 2s^2 2p^6 3s^2 3p^6 3d^5 4s^1
C
1s^2 2s^2 2p^6 3s^2 3p^6 4s^1 3d^4
D
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^3
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1
Identify the atomic number of vanadium, which is 23. This means a neutral vanadium atom has 23 electrons to place in orbitals.
Recall the order of filling orbitals according to the Aufbau principle: \(1s \rightarrow 2s \rightarrow 2p \rightarrow 3s \rightarrow 3p \rightarrow 4s \rightarrow 3d\).
Fill the orbitals in order with electrons, remembering that the \$4s$ orbital fills before the \$3d$ orbital. So, after filling \$1s^2 2s^2 2p^6 3s^2 3p^6$, place electrons in \$4s$ before \$3d$.
Distribute the remaining electrons (after filling up to \$3p^6$) into \$4s$ and \$3d$ orbitals. Since \$4s$ fills first, place 2 electrons in \$4s$ and the remaining 3 electrons in \$3d$ to total 23 electrons.
Verify that the electron configuration matches the total number of electrons (23) and follows the correct filling order and Hund's rule, resulting in \$1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^3$.