객관식
One mole (mol) of glucose (molecular mass = 180 daltons) is:
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2. Atoms & Elements
Mole Concept
Multiple Choice
How many moles of NaCl are present in 0.500 L of a 1.5 M NaCl solution?
A
1.5 mol
B
0.50 mol
C
0.75 mol
D
0.33 mol
검증된 단계별 안내1
Identify the given information: the volume of the NaCl solution is 0.500 L and the molarity (M) is 1.5 mol/L.
Recall the definition of molarity: \(\text{Molarity} = \frac{\text{moles of solute}}{\text{liters of solution}}\).
Rearrange the molarity formula to solve for moles of solute: \(\text{moles of solute} = \text{Molarity} \times \text{Volume}\).
Substitute the known values into the equation: \(\text{moles of NaCl} = 1.5\ \text{mol/L} \times 0.500\ \text{L}\).
Multiply the values to find the number of moles of NaCl present in the solution.
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