객관식
In the reaction between ammonia (NH_3) and phosphoric acid (H_3PO_4) to form ammonium phosphate ((NH_4)_3PO_4), how many moles of ammonia are required to react completely with 3 moles of phosphoric acid?
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3. Chemical Reactions
Stoichiometry
Multiple Choice
When 3 moles of hydrogen gas (H_2) react completely with 3 moles of oxygen gas (O_2) according to the equation 2H_2 + O_2 → 2H_2O, how many grams of water (H_2O) are produced?
A
90 grams
B
36 grams
C
108 grams
D
54 grams
검증된 단계별 안내1
Write down the balanced chemical equation: \[2H_2 + O_2 \rightarrow 2H_2O\].
Identify the mole ratio between hydrogen gas and water from the balanced equation. For every 2 moles of \[H_2\], 2 moles of \[H_2O\] are produced, so the ratio is 1:1.
Determine the limiting reactant by comparing the given moles of \[H_2\] and \[O_2\] with the stoichiometric ratio. Since 3 moles of \[H_2\] require 1.5 moles of \[O_2\] (based on the ratio 2:1), and 3 moles of \[O_2\] are available, \[H_2\] is the limiting reactant.
Calculate the moles of water produced, which will be equal to the moles of the limiting reactant \[H_2\] (3 moles) because of the 1:1 mole ratio.
Calculate the mass of water produced by multiplying the moles of \[H_2O\] by its molar mass: \[\text{mass} = \text{moles} \times \text{molar mass} = 3 \times 18 \text{ g/mol}\].
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