객관식
Which of the following best describes the molecular geometry of a water (H_2O) molecule?
105
views
12. Molecular Shapes & Valence Bond Theory
Molecular Geometry
객관식
Which molecular geometry is expected for XeF_4?
A
Tetrahedral
B
Trigonal bipyramidal
C
Square planar
D
Octahedral
검증된 단계별 안내1
Identify the central atom and the number of valence electrons it has. For XeF_4, the central atom is xenon (Xe), which has 8 valence electrons.
Count the total number of electrons around the central atom by adding the valence electrons of xenon and the electrons contributed by the four fluorine atoms. Each fluorine contributes 1 electron for bonding, so total bonding electrons are 4 pairs.
Determine the number of electron pairs around the central atom, including both bonding pairs and lone pairs. Xenon in XeF_4 has 4 bonding pairs (from the 4 fluorine atoms) and 2 lone pairs, making a total of 6 electron pairs.
Use the VSEPR (Valence Shell Electron Pair Repulsion) theory to predict the electron pair geometry. Six electron pairs arrange themselves in an octahedral geometry to minimize repulsion.
Consider the positions of the lone pairs. The two lone pairs occupy positions opposite each other to minimize repulsion, leaving the four fluorine atoms in a square planar arrangement around the xenon atom.
관련 영상
관련 실천
