How many lone pairs of electrons are present on the Xe atom in the ion XeF_6?
A
1
B
0
C
3
D
2
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검증된 단계별 안내
1
Step 1: Determine the total number of valence electrons for the central atom Xe. Xenon (Xe) is in group 18, so it has 8 valence electrons.
Step 2: Add the valence electrons contributed by the fluorine atoms. Each fluorine atom contributes 1 electron, and there are 6 fluorine atoms, so add 6 electrons.
Step 3: Since the species is neutral (XeF_6), the total valence electrons are the sum of Xe and F electrons: \(8 + 6 = 14\) electrons.
Step 4: Use the total valence electrons to determine the electron pairs around Xe. Divide the total electrons by 2 to get the number of electron pairs: \(\frac{14}{2} = 7\) pairs.
Step 5: Assign 6 of these pairs as bonding pairs to the 6 fluorine atoms. The remaining pairs are lone pairs on Xe. Therefore, the number of lone pairs on Xe is \(7 - 6 = 1\).