객관식
A student dilutes 25.0 mL of an HCl solution to a final volume of 250.0 mL. The concentration of the diluted solution is found to be 0.15 M. What was the original concentration of the HCl solution before dilution?
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6. Chemical Quantities & Aqueous Reactions
Molarity
Multiple Choice
What is the molarity of a solution containing 1.54 mol of NaOH in 2.5 \(\times\) 10^2 mL of solution?
A
6.16 M
B
0.154 M
C
0.616 M
D
1.54 M
검증된 단계별 안내1
Identify the formula for molarity, which is defined as the number of moles of solute divided by the volume of the solution in liters: \(M = \frac{\text{moles of solute}}{\text{volume of solution in liters}}\).
Convert the volume of the solution from milliliters to liters because molarity requires volume in liters. Use the conversion factor \(1\,\text{L} = 1000\,\text{mL}\): \(\text{volume in liters} = \frac{2.5 \times 10^2\,\text{mL}}{1000}\).
Substitute the given values into the molarity formula: moles of NaOH = 1.54 mol, and volume in liters as calculated in the previous step.
Calculate the molarity by dividing the moles of NaOH by the volume in liters: \(M = \frac{1.54}{\text{volume in liters}}\).
Interpret the result to determine which of the provided answer choices matches the calculated molarity.
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