객관식
Which of the following is the mass in grams of 4.25 × 10^3 mol of N_2?
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2. Atoms & Elements
Calculating Molar Mass
객관식
If seawater contains 3.2 × 10^{-9} g of gold per liter, how many grams of gold are present in 1.00 L of seawater?
A
1.0 × 10^{-3} g
B
6.02 × 10^{23} g
C
0.32 g
D
3.2 × 10^{-9} g
검증된 단계별 안내1
Identify the given information: the concentration of gold in seawater is 3.2 \(\times\) 10^{-9} grams per liter.
Recognize that the problem asks for the amount of gold in 1.00 liter of seawater, which means the volume is 1.00 L.
Use the relationship between concentration and amount: \(\n\[\nAmount\) of gold (g) = Concentration (g/L) \(\times\) Volume (L) \(\n\]\nExpressed\) as: \(\text{mass} = (3.2 \times 10^{-9} \text{ g/L}) \times (1.00 \text{ L})\)
Multiply the concentration by the volume to find the total grams of gold in 1.00 L of seawater. Since the volume is 1.00 L, the mass will be equal to the concentration value.
Confirm that the units of liters cancel out, leaving the mass in grams, which matches the given concentration value.
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