객관식
In the Lewis dot structure of ammonia (NH_3), how many lone pairs are present on the nitrogen atom?
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11. Bonding & Molecular Structure
Lewis Dot Structures: Neutral Compounds
객관식
How many electrons (including both lone pairs and bonding pairs) are shown in the correct Lewis dot structure of the neutral compound HClO?
A
14
B
16
C
18
D
20
검증된 단계별 안내1
Step 1: Determine the total number of valence electrons for the neutral compound HClO by adding the valence electrons of each atom. Hydrogen (H) has 1 valence electron, chlorine (Cl) has 7 valence electrons, and oxygen (O) has 6 valence electrons. So, total valence electrons = 1 + 7 + 6.
Step 2: Draw the skeletal structure of HClO, typically with chlorine as the central atom bonded to hydrogen and oxygen. Connect the atoms with single bonds initially. Each single bond represents 2 shared electrons.
Step 3: Distribute the remaining valence electrons as lone pairs around the atoms to satisfy the octet rule (or duet for hydrogen). Remember that hydrogen only needs 2 electrons, while oxygen and chlorine generally need 8 electrons each.
Step 4: Count all the electrons shown in the Lewis structure, including both bonding pairs (shared electrons in bonds) and lone pairs (non-bonding electrons) on all atoms.
Step 5: Verify that the total number of electrons counted matches the total valence electrons calculated in Step 1, ensuring the Lewis structure is correct and complete.
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