Which of the following statements correctly describes the Lewis dot structure of the neutral compound PF3?
A
Phosphorus is surrounded by four single bonds to fluorine atoms and no lone pairs.
B
Phosphorus is surrounded by three single bonds to fluorine atoms and one lone pair.
C
Phosphorus forms three double bonds with fluorine atoms and has no lone pairs.
D
Phosphorus forms two single bonds and one double bond with fluorine atoms, with one lone pair.
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검증된 단계별 안내
1
Step 1: Determine the total number of valence electrons available for the molecule PF3. Phosphorus (P) is in group 15 and has 5 valence electrons, and each fluorine (F) atom is in group 17 with 7 valence electrons. Since there are three fluorine atoms, calculate the total valence electrons as \(5 + 3 \times 7\).
Step 2: Use the total valence electrons to draw a preliminary Lewis structure. Place phosphorus as the central atom and connect it to each fluorine atom with a single bond. Each single bond represents 2 electrons.
Step 3: Distribute the remaining electrons to satisfy the octet rule for the fluorine atoms first, since fluorine is more electronegative and typically completes its octet with lone pairs.
Step 4: After placing lone pairs on the fluorine atoms, check how many electrons remain for the phosphorus atom. Determine if phosphorus has a complete octet or if it has any lone pairs left.
Step 5: Analyze the bonding and lone pairs on phosphorus. Since phosphorus has 5 valence electrons and forms three single bonds (each bond uses 1 electron from phosphorus), phosphorus will have one lone pair remaining. This matches the description: phosphorus is surrounded by three single bonds to fluorine atoms and one lone pair.