Which of the following correctly states the number of valence electrons in ICl and describes the arrangement of electrons in its Lewis structure?
A
ICl has 16 valence electrons; the Lewis structure shows a triple bond between I and Cl, with one lone pair on each atom.
B
ICl has 12 valence electrons; the Lewis structure shows a double bond between I and Cl, with two lone pairs on each atom.
C
ICl has 14 valence electrons; the Lewis structure shows a single bond between I and Cl, with three lone pairs on each atom.
D
ICl has 8 valence electrons; the Lewis structure shows a single bond between I and Cl, with two lone pairs on each atom.
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1
Determine the number of valence electrons for each atom in ICl. Iodine (I) is in group 17 and has 7 valence electrons, and chlorine (Cl) is also in group 17 with 7 valence electrons.
Add the valence electrons from both atoms to find the total number of valence electrons in the ICl molecule: \(7 + 7 = 14\) valence electrons.
Draw a single bond between the iodine and chlorine atoms, which uses 2 electrons from the total valence electrons.
Distribute the remaining electrons as lone pairs to satisfy the octet rule for both atoms. Since 2 electrons are used in the bond, 12 electrons remain to be placed as lone pairs.
Place three lone pairs (6 electrons) on each atom to complete their octets, resulting in a Lewis structure with a single bond between I and Cl and three lone pairs on each atom.