What volume in milliliters of concentrated HCl (12 M) is required to prepare 1500 mL of a 3.5 M HCl solution?
A
438 mL
B
525 mL
C
150 mL
D
292 mL
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1
Identify the dilution equation to use, which relates the concentrations and volumes before and after dilution: \(C_1 \times V_1 = C_2 \times V_2\), where \(C_1\) and \(V_1\) are the concentration and volume of the concentrated solution, and \(C_2\) and \(V_2\) are those of the diluted solution.
Assign the known values: \(C_1 = 12\,M\) (concentrated HCl), \(C_2 = 3.5\,M\) (desired concentration), and \(V_2 = 1500\,mL\) (final volume of the diluted solution).
Rearrange the dilution equation to solve for the volume of concentrated HCl needed: \(V_1 = \frac{C_2 \times V_2}{C_1}\).
Substitute the known values into the rearranged equation: \(V_1 = \frac{3.5\,M \times 1500\,mL}{12\,M}\).
Calculate \(V_1\) to find the volume of concentrated HCl required to prepare the 1500 mL of 3.5 M solution.