객관식
How many moles of NaNO3 are present in a 44.0 g sample?
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2. Atoms & Elements
Mole Concept
객관식
How many atoms are present in 179.0 g of iridium (Ir)? (Atomic mass of Ir = 192.2 g/mol)
A
1.12 × 10^{24} atoms
B
9.36 × 10^{22} atoms
C
3.45 × 10^{24} atoms
D
5.61 × 10^{23} atoms
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검증된 단계별 안내1
Identify the given information: mass of iridium (Ir) is 179.0 g and the atomic mass of Ir is 192.2 g/mol.
Calculate the number of moles of iridium using the formula: \(\text{moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{179.0\ \text{g}}{192.2\ \text{g/mol}}\).
Recall that one mole of any element contains Avogadro's number of atoms, which is \(6.022 \times 10^{23}\) atoms/mol.
Calculate the total number of atoms by multiplying the moles of iridium by Avogadro's number: \(\text{atoms} = \text{moles} \times 6.022 \times 10^{23}\).
Express the final answer in scientific notation to compare with the given options.
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