Determine if each of the following compounds will create an acidic, basic or neutral solution. a) LiC2H3O2 b) C6H5NH3Br
A
a) acidic b) basic
B
a) acidic b) acidic
C
a) basic b) acidic
D
a) basic b) basic
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1
Identify the ions present in each compound. For LiC₂H₃O₂, the ions are Li⁺ and C₂H₃O₂⁻ (acetate ion). For C₆H₅NH₃Br, the ions are C₆H₅NH₃⁺ (anilinium ion) and Br⁻.
Determine the nature of each ion. Li⁺ is a cation from a strong base (LiOH), which does not affect pH. C₂H₃O₂⁻ is the conjugate base of acetic acid, a weak acid, and can accept protons, making the solution basic.
For C₆H₅NH₃Br, C₆H₅NH₃⁺ is the conjugate acid of aniline, a weak base, and can donate protons, making the solution acidic. Br⁻ is the conjugate base of a strong acid (HBr) and does not affect pH.
Assess the overall effect of the ions in solution. For LiC₂H₃O₂, since the acetate ion makes the solution basic, the overall solution is basic. For C₆H₅NH₃Br, the anilinium ion makes the solution acidic, so the overall solution is acidic.
Conclude the nature of the solutions: LiC₂H₃O₂ results in a basic solution, and C₆H₅NH₃Br results in an acidic solution.