Which of the following is the correct Lewis structure for OSF4, where sulfur (S) is the central atom and all atoms have a formal charge of zero?
A
S is bonded to one oxygen (O) atom with a single bond and four fluorine (F) atoms with single bonds, with one lone pair on the sulfur.
B
S is bonded to one oxygen (O) atom with a double bond and four fluorine (F) atoms with single bonds, with two lone pairs on the oxygen.
C
S is bonded to one oxygen (O) atom with a double bond and four fluorine (F) atoms with single bonds, with one lone pair on the sulfur.
D
S is bonded to one oxygen (O) atom with a single bond and four fluorine (F) atoms with double bonds, with no lone pairs on the oxygen.
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검증된 단계별 안내
1
Identify the central atom in the molecule. In OSF4, sulfur (S) is the central atom.
Determine the total number of valence electrons available. Oxygen (O) has 6 valence electrons, sulfur (S) has 6 valence electrons, and each fluorine (F) has 7 valence electrons. Calculate the total: 6 (O) + 6 (S) + 4 * 7 (F) = 40 valence electrons.
Arrange the atoms around the central sulfur atom. Connect sulfur to oxygen with a double bond and to each fluorine with a single bond. This uses 2 electrons for the S=O bond and 8 electrons for the S-F bonds (2 electrons per bond).
Distribute the remaining electrons to satisfy the octet rule. Place two lone pairs on the oxygen atom to complete its octet, using 4 electrons. Place one lone pair on the sulfur atom, using 2 electrons.
Verify the formal charges. Calculate the formal charge for each atom using the formula: Formal Charge = Valence Electrons - (Non-bonding Electrons + 1/2 Bonding Electrons). Ensure all atoms have a formal charge of zero.