How many atoms of chlorine are present in 1.00 mol of chlorine gas (Cl_2)?
A
3.011 × 10^{23} atoms
B
6.022 × 10^{23} atoms
C
2.000 × 10^{23} atoms
D
1.204 × 10^{24} atoms
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검증된 단계별 안내
1
Recognize that chlorine gas (Cl_2) is a diatomic molecule, meaning each molecule contains 2 chlorine atoms.
Recall Avogadro's number, which states that 1 mole of any substance contains \(6.022 \times 10^{23}\) entities (in this case, molecules).
Calculate the total number of chlorine atoms by multiplying the number of molecules by 2, since each molecule has 2 atoms: \(\text{Number of atoms} = 2 \times 6.022 \times 10^{23}\).
Set up the multiplication to find the total atoms: \(2 \times 6.022 \times 10^{23} = 1.2044 \times 10^{24}\) atoms.
Interpret the result as the total number of chlorine atoms present in 1.00 mole of Cl_2 gas.