객관식
Which three variables are directly related in the Clausius-Clapeyron equation?
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13. Liquids, Solids & Intermolecular Forces
Clausius-Clapeyron Equation
객관식
Vapor pressure measurements at various temperature values are given below. Determine the molar heat of vaporization for cyclohexane.
A
11,520 J/mol
B
72,193 J/mol
C
33,147 J/mol
D
52,968 J/mol
검증된 단계별 안내1
Convert the given temperatures from Celsius to Kelvin by adding 273.15 to each temperature value. This is necessary because the Clausius-Clapeyron equation requires absolute temperature.
Calculate the natural logarithm of the vapor pressure values (P) given in mmHg for each temperature.
Use the Clausius-Clapeyron equation in its linear form: \(\ln P = -\frac{\Delta H_{vap}}{R} \cdot \frac{1}{T} + C\), where \(\Delta H_{vap}\) is the molar heat of vaporization, \(R\) is the gas constant (8.314 J/mol·K), \(T\) is the temperature in Kelvin, and \(C\) is a constant.
Plot \(\ln P\) versus \(\frac{1}{T}\) and determine the slope of the resulting straight line. The slope will be equal to \(-\frac{\Delta H_{vap}}{R}\).
Calculate the molar heat of vaporization \(\Delta H_{vap}\) by multiplying the slope by \(-R\): \(\Delta H_{vap} = -\text{slope} \times R\).
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