Which of the following represents the third ionization of Mn?
A
Mn− (g) + e− → 2 Mn2− (g)
B
Mn2+ (g) → Mn3+ (g) + e−
C
Mn2− (g) + e− → 2 Mn3− (g)
D
Mn (g) → Mn3+ (g) + 3 e−
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1
Understand that ionization refers to the process of removing electrons from an atom or ion, resulting in a positively charged species.
The first ionization removes one electron from the neutral atom: \(\text{Mn} (g) \rightarrow \text{Mn}^{+} (g) + e^{-}\).
The second ionization removes a second electron from the singly charged ion: \(\text{Mn}^{+} (g) \rightarrow \text{Mn}^{2+} (g) + e^{-}\).
The third ionization removes a third electron from the doubly charged ion: \(\text{Mn}^{2+} (g) \rightarrow \text{Mn}^{3+} (g) + e^{-}\).
Therefore, the third ionization of Mn is represented by the equation \(\text{Mn}^{2+} (g) \rightarrow \text{Mn}^{3+} (g) + e^{-}\), which matches the correct answer.