What is the charge of the metal ion in the complex ion Fe(NH_3)_2Br_4^{2-}? (Omit the + sign in your answer.)
A
4
B
2
C
3
D
1
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1
Identify the overall charge of the complex ion, which is given as \$2-\( (i.e., \)-2$).
Determine the charges of the ligands attached to the metal ion. Ammonia (\(NH_3\)) is a neutral ligand with a charge of 0, and bromide ($Br^-$) is an anionic ligand with a charge of \(-1\) each.
Calculate the total charge contributed by the ligands: since there are 2 \(NH_3\) ligands (each 0 charge) and 4 $Br^-$ ligands (each \(-1\) charge), the total ligand charge is \(2 \times 0 + 4 \times (-1) = -4\).
Let the charge of the metal ion be \(x\). The sum of the metal ion charge and the ligand charges equals the overall charge of the complex ion, so set up the equation: \(x + (-4) = -2\).
Solve the equation for \(x\) to find the charge of the metal ion: \(x = -2 + 4\).