객관식
Calculate the number of grams of KOH in 250.0 mL of a 0.189 M solution.
556
views
6. Chemical Quantities & Aqueous Reactions
Molarity
Multiple Choice
Determine the molarity of a solution prepared by dissolving 11.5 g of NaOH to form a 250.0 mL solution. (Molar mass of NaOH = 40.00 g/mol)
A
0.230 M
B
0.920 M
C
0.460 M
D
0.115 M
검증된 단계별 안내1
First, calculate the number of moles of NaOH using the formula: \( \text{moles} = \frac{\text{mass}}{\text{molar mass}} \). Here, the mass of NaOH is 11.5 g and the molar mass is 40.00 g/mol.
Substitute the given values into the formula: \( \text{moles of NaOH} = \frac{11.5 \text{ g}}{40.00 \text{ g/mol}} \).
Next, convert the volume of the solution from milliliters to liters, since molarity is expressed in moles per liter. The volume of the solution is 250.0 mL, which is equivalent to 0.250 L.
Now, use the formula for molarity: \( \text{Molarity} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \).
Substitute the calculated moles of NaOH and the volume in liters into the molarity formula to find the molarity of the solution.
Related Videos
Related Practice
