Join thousands of students who trust us to help them ace their exams!
Multiple Choice
A solution of water (Kb=0.512 °C/m) and glucose boils at 103.56 °C. What is the molal concentration of glucose in this solution? Assume that the boiling point of pure water is 100.00 °C.
A
7.00 m
B
7.10 m
C
6.95 m
D
6.50 m
0 댓글
검증된 단계별 안내
1
Identify the boiling point elevation formula: ΔT_b = i * K_b * m, where ΔT_b is the boiling point elevation, i is the van't Hoff factor (which is 1 for glucose, a non-electrolyte), K_b is the ebullioscopic constant, and m is the molality.
Calculate the boiling point elevation (ΔT_b) by subtracting the boiling point of pure water from the boiling point of the solution: ΔT_b = 103.56 °C - 100.00 °C.
Substitute the known values into the boiling point elevation formula: ΔT_b = 1 * 0.512 °C/m * m.
Rearrange the formula to solve for molality (m): m = ΔT_b / (i * K_b).
Substitute the calculated ΔT_b and the given K_b into the rearranged formula to find the molal concentration of glucose.