A proton in a linear accelerator has a de Broglie wavelength of 132 pm. What is the speed of the proton?

What is the de Broglie wavelength of an electron traveling at 1.35 x 10^5 m/s?

In a technique used for surface analysis called Auger electron spectroscopy (AES), electrons are accelerated toward a metal surface. These electrons cause the emissions of secondary electrons—called Auger electrons—from the metal surface. The kinetic energy of the Auger electrons depends on the composition of the surface. The presence of oxygen atoms on the surface results in Auger electrons with a kinetic energy of approximately 506 eV. What is the de Broglie wavelength of one of these electrons? [KE = 1/2mv^2; 1 electron volt (eV) = 1.602 * 10^(-19) J]

In order for a thermonuclear fusion reaction of two deuterons (2^1H^+) to take place, the deuterons must collide and each must have a velocity of about 1 * 10^6 m/s. Find the wavelength of such a deuteron.

A typical electron velocity is 7.27 x 10^6 m/s. Calculate the de Broglie wavelength of an electron having this velocity:

Calculate the de Broglie wavelength of a 143 g baseball traveling at 83 mph. (Note: 1 mph = 0.44704 m/s)

Calculate the de Broglie wavelength of a hydrogen atom traveling at 495 m/s. Assume the mass of a hydrogen atom is approximately 1.67 x 10^-27 kg.

Calculate the energy of a neutron whose de Broglie wavelength is 0.7 Å. Assume the mass of the neutron is 1.675 x 10^-27 kg and use Planck's constant h = 6.626 x 10^-34 J·s.