미해결 질문
Rapid oxidation of a substance, accompanied by the production of heat and light.
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3. Chemical Reactions
Combustion Analysis
객관식
What is the standard enthalpy change for the combustion of one mole of benzene (C6H6) based on the given reaction: 2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(l); ΔHrxn° = -6534 kJ?
A
-13068 kJ/mol
B
-2178 kJ/mol
C
-6534 kJ/mol
D
-3267 kJ/mol
검증된 단계별 안내1
Identify the given reaction: 2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(l) with ΔHrxn° = -6534 kJ. This is the enthalpy change for the combustion of 2 moles of benzene.
To find the enthalpy change for the combustion of one mole of benzene, recognize that the given ΔHrxn° corresponds to 2 moles of C6H6.
Use the relationship: ΔH for 1 mole = (ΔH for 2 moles) / 2. This is because the reaction as written involves 2 moles of benzene.
Substitute the given ΔHrxn° value into the equation: ΔH for 1 mole = (-6534 kJ) / 2.
Calculate the result to find the standard enthalpy change for the combustion of one mole of benzene.
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