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Multiple Choice
What final temperature will 120 g of benzene at 7°C have after it absorbs 2.20 kJ of heat? The specific heat capacity (Cp) of benzene is 1.74 J/g°C.
A
10.15°C
B
8.05°C
C
9.20°C
D
11.30°C
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1
Identify the given values: mass (m) = 120 g, initial temperature (T_initial) = 7°C, heat absorbed (q) = 2.20 kJ, and specific heat capacity (Cp) = 1.74 J/g°C.
Convert the heat absorbed from kilojoules to joules: 2.20 kJ = 2200 J.
Use the formula for heat transfer: q = m * Cp * ΔT, where ΔT is the change in temperature (T_final - T_initial).
Rearrange the formula to solve for the final temperature (T_final): T_final = T_initial + (q / (m * Cp)).
Substitute the known values into the equation: T_final = 7°C + (2200 J / (120 g * 1.74 J/g°C)).