Join thousands of students who trust us to help them ace their exams!
Multiple Choice
Given the reaction 2COF2(g) ⇌ CO2(g) + CF4(g) with an equilibrium constant Kp = 2.2 × 10^6 at 298 K, what is the equilibrium constant Kp for the reaction 4COF2(g) ⇌ 2CO2(g) + 2CF4(g)?
A
2.2 × 10^6
B
4.8 × 10^12
C
1.1 × 10^6
D
1.0 × 10^13
0 댓글
검증된 단계별 안내
1
Identify the given reaction and its equilibrium constant: 2COF2(g) ⇌ CO2(g) + CF4(g) with Kp = 2.2 × 10^6.
Recognize that the new reaction is 4COF2(g) ⇌ 2CO2(g) + 2CF4(g), which is a multiple of the original reaction.
Understand that when a chemical equation is multiplied by a factor, the equilibrium constant is raised to the power of that factor.
In this case, the original reaction is multiplied by 2, so the new equilibrium constant Kp is (2.2 × 10^6)^2.
Calculate the new Kp by squaring the original Kp value: (2.2 × 10^6)^2, which will give the equilibrium constant for the new reaction.