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Multiple Choice
Sodium reacts violently with water according to the equation: 2 Na(s) + 2 H2O(l) → 2 NaOH(aq) + H2(g). The resulting solution has a higher temperature than the water prior to the addition of sodium. What are the signs of ΔH° and ΔS° for this reaction?
A
ΔH° is negative, ΔS° is positive
B
ΔH° is negative, ΔS° is negative
C
ΔH° is positive, ΔS° is negative
D
ΔH° is positive, ΔS° is positive
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1
Identify the type of reaction: Sodium reacts with water to form sodium hydroxide and hydrogen gas. This is an exothermic reaction, as indicated by the increase in temperature of the solution.
Determine the sign of ΔH°: Since the reaction releases heat (exothermic), the enthalpy change (ΔH°) is negative.
Analyze the change in entropy (ΔS°): The reaction produces gas (H2) from solid (Na) and liquid (H2O), which increases the disorder of the system. Therefore, the entropy change (ΔS°) is positive.
Consider the states of matter: The formation of a gas from a solid and liquid generally leads to an increase in entropy, supporting the positive ΔS°.
Conclude the signs: Based on the exothermic nature and the increase in disorder, the signs are ΔH° is negative and ΔS° is positive.