- 작성 시간을 절약하려면 워크시트를 다운로드하세요
- 연습 문제를 풀기 시작해
- 막히면 영상 해답을 보세요
- 더 많은 인사이트를 원하시면 요약을 참고하세요

Carbon dioxide, CO2, is previously used as a refrigerant. Raw CO2 gas is a by-product during the fermentation of sugars. To lessen the amount of CO2 that is released into the atmosphere, raw CO2 gas undergoes treatment and can be liquefied. The treated CO2 gas is stored in tank A and the liquefied CO2 is stored in tank B. The solubility of O2 gas in the liquefied CO2 is 0.0150 mL O2 per 100 mL liquefied CO2 whereas the treated CO2 gas contains 0.0200% O2 gas by volume. Listed in the following table are the parameters of tank A and tank B. Calculate the moles of O2 gas present in tank A and tank B.
Volume (L) Pressure (atm) Temperature (°C)
Tank A 250 1.00 atm 35.0°C
Tank B 250 75.0 atm 20.0°C
What is the average molecular weight of moist air? Use the information below:

A 12.6 L mixture of ethane (C2H6) and butane (C4H10) is stored at 751 mmHg and 298 K. Calculate the mole fraction of ethane given that the mixture produces 982 kJ of heat when burned. Assume that the water produced by the reaction is a gas.
Calculate the mole fraction of oxygen in the air. If air contains 18.0 g oxygen gas at 285 K at 1.20 atm, what is the volume of air?

Determine the mole fraction of each component given the following data:
Component Mass (g)
N2 0.700
O2 0.800
Cl2 1.77