Write an equation for the reaction in which H2C6H7O5-1aq2 acts as a base in H2O1l2.

검증된 단계별 안내

Step 1: Identify the base in the reaction. In this case, the base is H2C6H7O5-1(aq). A base is a substance that can accept a proton (H+).

Step 2: Identify the other reactant in the reaction. In this case, it is H2O(l). Water can act as both an acid and a base, but in this reaction, it will act as an acid, meaning it will donate a proton (H+).

Step 3: Write the reaction equation. The base (H2C6H7O5-1) will accept a proton from the acid (H2O), forming its conjugate acid (H3C6H7O5) and the conjugate base of water (OH-).

Step 4: The final equation for the reaction is: H2C6H7O5-1(aq) + H2O(l) ⇌ H3C6H7O5(aq) + OH-(aq).

Step 5: Remember that in an acid-base reaction, the acid donates a proton and the base accepts a proton. The substance that the acid becomes after donating a proton is called its conjugate base, and the substance that the base becomes after accepting a proton is called its conjugate acid.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Acid-Base Theory

Acid-base theory explains the behavior of acids and bases in chemical reactions. According to the Brønsted-Lowry theory, an acid is a proton donor, while a base is a proton acceptor. In the context of the given question, H2C6H7O5- acts as a base by accepting a proton (H+) from water, which is crucial for writing the correct reaction equation.

Dissociation of Water

Water (H2O) can dissociate into hydronium (H3O+) and hydroxide (OH-) ions. This equilibrium is essential in acid-base reactions, as it provides the protons that acids donate and the hydroxide ions that bases can interact with. Understanding this dissociation helps in predicting the products of the reaction when H2C6H7O5- acts as a base.

Chemical Equation Representation

A chemical equation represents the reactants and products of a chemical reaction. It must be balanced to reflect the conservation of mass. In this case, writing the equation for the reaction involves showing H2C6H7O5- accepting a proton from water, resulting in the formation of H3O+ and the conjugate acid of H2C6H7O5-, which is essential for accurately depicting the reaction.