You are asked to prepare a pH = 4.00 buffer starting from 1.50 L of 0.0200 M solution of benzoic acid 1C6H5COOH2 and any amount you need of sodium benzoate 1C6H5COONa2. (b) How many grams of sodium benzoate should be added to prepare the buffer? Neglect the small volume change that occurs when the sodium benzoate is added.
Ch.17 - Additional Aspects of Aqueous Equilibria
17장, 문제 27b
A buffer contains 0.10 mol of acetic acid and 0.13 mol of sodium acetate in 1.00 L. (b) What is the pH of the buffer after the addition of 0.02 mol of KOH?
검증된 단계별 안내1
Identify the components of the buffer system: acetic acid (CH₃COOH) and sodium acetate (CH₃COONa).
Recognize that the addition of KOH, a strong base, will react with the acetic acid in the buffer.
Write the chemical equation for the reaction: CH₃COOH + OH⁻ → CH₃COO⁻ + H₂O.
Calculate the moles of acetic acid and acetate after the reaction with KOH. Subtract the moles of KOH from the moles of acetic acid and add the moles of KOH to the moles of acetate.
Use the Henderson-Hasselbalch equation to find the new pH: \( \text{pH} = \text{pK}_a + \log \left( \frac{[\text{CH}_3\text{COO}^-]}{[\text{CH}_3\text{COOH}]} \right) \), where \( \text{pK}_a \) is the negative logarithm of the acid dissociation constant of acetic acid.

비슷한 문제에 대한 검증된 영상 답변:
이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
3m주요 개념
질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.
Buffer Solutions
A buffer solution is a system that resists changes in pH upon the addition of small amounts of acid or base. It typically consists of a weak acid and its conjugate base, which work together to neutralize added acids or bases. In this case, acetic acid (weak acid) and sodium acetate (conjugate base) form a buffer that can maintain pH stability.
추천 영상:
가이드 코스
Buffer Solutions
Henderson-Hasselbalch Equation
The Henderson-Hasselbalch equation is a mathematical formula used to calculate the pH of a buffer solution. It is expressed as pH = pKa + log([A-]/[HA]), where pKa is the negative logarithm of the acid dissociation constant, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the weak acid. This equation is essential for determining the pH after the addition of KOH.
추천 영상:
가이드 코스
Henderson-Hasselbalch Equation
Neutralization Reaction
A neutralization reaction occurs when an acid reacts with a base to form water and a salt, effectively reducing the concentration of both species. In this scenario, the addition of KOH (a strong base) will react with acetic acid, decreasing its concentration while increasing the concentration of acetate ions. Understanding this reaction is crucial for calculating the new pH of the buffer.
추천 영상:
가이드 코스
Lewis Dot Structures: Neutral Compounds
관련 실천
교과서 질문
1095
views
교과서 질문
A buffer contains 0.10 mol of acetic acid and 0.13 mol of sodium acetate in 1.00 L. (a) What is the pH of this buffer?
678
views
교과서 질문
A buffer contains 0.10 mol of acetic acid and 0.13 mol of sodium acetate in 1.00 L. (c) What is the pH of the buffer after the addition of 0.02 mol of HNO3?
585
views
교과서 질문
You are asked to prepare a pH = 4.00 buffer starting from 1.50 L of 0.0200 M solution of benzoic acid 1C6H5COOH2 and any amount you need of sodium benzoate 1C6H5COONa2. (a) What is the pH of the benzoic acid solution prior to adding sodium benzoate?
327
views
교과서 질문
(a) What is the ratio of HCO3- to H2CO3 in blood of pH 7.4?
1960
views
