Skip to main content
Ch.17 - Additional Aspects of Aqueous Equilibria
Brown - Chemistry: The Central Science 14th Edition
Brown14th EditionChemistry: The Central ScienceISBN: 9780134414232당신이 사용하는 게 아니라요?교과서 변경
17장, 문제 58c

Calculate the solubility of LaF3 in grams per liter in (c) 0.050 M LaCl3 solution.

검증된 단계별 안내
1
Identify the dissolution reaction of LaF_3: LaF_3(s) \(\rightleftharpoons\) La^{3+}(aq) + 3F^{-}(aq).
Write the expression for the solubility product constant (K_{sp}) for LaF_3: K_{sp} = [La^{3+}][F^{-}]^3.
Recognize that in a 0.050 M LaCl_3 solution, the concentration of La^{3+} ions is already 0.050 M due to the complete dissociation of LaCl_3.
Assume the solubility of LaF_3 is 's' mol/L. The concentration of F^{-} ions will be 3s, and the concentration of La^{3+} ions will be 0.050 + s.
Substitute these concentrations into the K_{sp} expression and solve for 's', considering that 's' is small compared to 0.050 M, so 0.050 + s \(\approx\) 0.050.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
7m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Solubility Product Constant (Ksp)

The solubility product constant (Ksp) is a numerical value that represents the equilibrium between a solid and its ions in a saturated solution. For a salt like LaF3, Ksp is determined by the concentrations of the ions produced when the salt dissolves. Understanding Ksp is essential for calculating solubility, especially in the presence of common ions, as it helps predict how much of the salt can dissolve in a given solution.
추천 영상:
가이드 코스
01:47
Solubility Product Constant

Common Ion Effect

The common ion effect refers to the decrease in solubility of a salt when a common ion is added to the solution. In this case, the presence of LaCl3 introduces La³⁺ ions, which shifts the dissolution equilibrium of LaF3 to the left, reducing its solubility. This concept is crucial for understanding how the solubility of LaF3 is affected in a solution already containing La³⁺ ions.
추천 영상:
가이드 코스
02:53
Common Ion Effect

Stoichiometry of Dissolution

Stoichiometry of dissolution involves understanding the ratio of ions produced when a compound dissolves. For LaF3, the dissolution can be represented as LaF3(s) ⇌ La³⁺(aq) + 3F⁻(aq). This stoichiometric relationship is important for calculating the concentrations of La³⁺ and F⁻ ions in solution, which are necessary for determining the solubility of LaF3 in the presence of LaCl3.
추천 영상:
가이드 코스
01:16
Stoichiometry Concept