Tooth enamel is composed of hydroxyapatite, whose simplest formula is Ca51PO423OH, and whose corresponding Ksp = 6.8 * 10-27. As discussed in the Chemistry and Life box on page 746, fluoride in fluorinated water or in toothpaste reacts with hydroxyapatite to form fluoroapatite, Ca51PO423F, whose Ksp = 1.0 * 10-60. (a) Write the expression for the solubility-constant for hydroxyapatite and for fluoroapatite.
Ch.17 - Additional Aspects of Aqueous Equilibria
17장, 문제 101
What is the pH of a 1 * 10^-3 M solution of Na3PO4? You can ignore the formation of H2PO4- and H3PO4^2-.
검증된 단계별 안내1
Identify the relevant chemical species in the solution: Na3PO4 dissociates completely in water to form 3 Na+ ions and 1 PO4^3- ion.
Recognize that PO4^3- is a base and can accept protons from water, forming OH- ions and HPO4^2- ions. The reaction is: \( \text{PO}_4^{3-} + \text{H}_2\text{O} \rightleftharpoons \text{HPO}_4^{2-} + \text{OH}^- \).
Use the base dissociation constant \( K_b \) for PO4^3- to find the concentration of OH- ions. The \( K_b \) can be calculated using the relation \( K_w = K_a \times K_b \), where \( K_w \) is the ion-product constant of water and \( K_a \) is the acid dissociation constant for the conjugate acid HPO4^2-.
Set up an expression for \( K_b \) using the concentrations: \( K_b = \frac{[\text{HPO}_4^{2-}][\text{OH}^-]}{[\text{PO}_4^{3-}]} \). Assume \([\text{HPO}_4^{2-}] = [\text{OH}^-] = x\) and \([\text{PO}_4^{3-}] = 1 \times 10^{-3} - x\), then solve for \( x \).
Calculate the pOH from the concentration of OH- ions using \( \text{pOH} = -\log[\text{OH}^-] \), and then find the pH using \( \text{pH} = 14 - \text{pOH} \).
주요 개념
질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.
pH and pOH
pH is a measure of the hydrogen ion concentration in a solution, defined as the negative logarithm of the hydrogen ion concentration (pH = -log[H+]). A lower pH indicates a more acidic solution, while a higher pH indicates a more basic solution. The pOH is similarly defined for hydroxide ions, and the relationship between pH and pOH is given by the equation pH + pOH = 14 at 25°C.
추천 영상:
가이드 코스
pH and pOH Calculations
Strong vs. Weak Bases
In chemistry, bases can be classified as strong or weak based on their ability to dissociate in water. Strong bases, like NaOH, completely dissociate into their ions, while weak bases only partially dissociate. Sodium phosphate (Na3PO4) is a strong base because it dissociates completely in solution, contributing to the increase in hydroxide ion concentration and thus raising the pH.
추천 영상:
가이드 코스
Strong vs Weak Bases
Dissociation of Sodium Phosphate
Sodium phosphate (Na3PO4) dissociates in water to produce sodium ions (Na+) and phosphate ions (PO4^3-). The phosphate ions can react with water to produce hydroxide ions (OH-), which increases the pH of the solution. Understanding this dissociation process is crucial for calculating the resulting pH of the solution, as it directly influences the concentration of hydroxide ions present.
추천 영상:
가이드 코스
Percent Dissociation Example
관련 실천
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교과서 질문
The solubility of CaCO3 is pH dependent. (b) Use the Kb expression for the CO32- ion to determine the equilibrium constant for the reaction CaCO3(s) + H2O(l) ⇌ Ca2+(aq) + HCO3-(aq) + OH-(aq)
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교과서 질문
A solid sample of Fe1OH23 is added to 0.500 L of 0.250 M
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point. What mass of Fe1OH23 was added to the H2SO4
solution?
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교과서 질문
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