Complete and balance the following nuclear equations by supplying the missing particle: (e) ⁵⁹₂₆Fe → ⁰_-1e + ?

검증된 단계별 안내

Step 1: Understand that in a nuclear equation, the sum of the atomic numbers (the lower number) and the sum of the atomic masses (the upper number) must be the same on both sides of the equation.

Step 2: Identify the atomic number and atomic mass of the given particle. For ⁵⁹₂₆Fe, the atomic number is 26 and the atomic mass is 59.

Step 3: Identify the atomic number and atomic mass of the electron (⁰_-1e). The atomic number is -1 and the atomic mass is 0.

Step 4: To balance the equation, find a particle that, when added to the electron, will have an atomic number and atomic mass that add up to those of the original particle. The atomic number should be 26 + 1 = 27 and the atomic mass should be 59 + 0 = 59.

Step 5: The missing particle is therefore ⁵⁹₂₇Co, because it has an atomic number of 27 and an atomic mass of 59, which balances the equation.

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주요 개념

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Nuclear Reactions

Nuclear reactions involve changes in an atom's nucleus and can result in the transformation of one element into another. These reactions are governed by the conservation of mass and charge, meaning that the total number of protons and neutrons must remain constant before and after the reaction.

Beta Decay

Beta decay is a type of radioactive decay in which a neutron in an atomic nucleus is transformed into a proton, emitting a beta particle (an electron or positron) in the process. This transformation increases the atomic number of the element by one while keeping the mass number unchanged, leading to the formation of a new element.

Balancing Nuclear Equations

Balancing nuclear equations requires ensuring that both the mass number and atomic number are conserved. This means that the sum of the mass numbers and the sum of the atomic numbers on both sides of the equation must be equal, allowing for the identification of any missing particles in the reaction.

Complete and balance the following nuclear equations by supplying the missing particle: (e) 5926Fe → 0-1e + ?