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Ch.22 - Chemistry of the Nonmetals
Brown - Chemistry: The Central Science 14th Edition
Brown14th EditionChemistry: The Central ScienceISBN: 9780134414232당신이 사용하는 게 아니라요?교과서 변경
22장, 문제 38

Complete the exercises below. Complete and balance the following equation: c. Na₂O₂ (s) + H₂O (l) →

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Step 1: Identify the reactants and products. The reactants are sodium peroxide (Na₂O₂) and water (H₂O). The products will include sodium hydroxide (NaOH) and oxygen gas (O₂).
Step 2: Write the unbalanced chemical equation using the identified reactants and products: Na₂O₂ (s) + H₂O (l) → NaOH (aq) + O₂ (g).
Step 3: Balance the sodium (Na) atoms. There are 2 Na atoms in Na₂O₂, so you need 2 NaOH molecules on the product side: Na₂O₂ (s) + H₂O (l) → 2 NaOH (aq) + O₂ (g).
Step 4: Balance the oxygen (O) atoms. There are 2 O atoms in Na₂O₂ and 1 O atom in H₂O, making a total of 3 O atoms on the reactant side. On the product side, there are 2 O atoms in 2 NaOH and 2 O atoms in O₂, making a total of 4 O atoms. Adjust the water to balance the oxygen: Na₂O₂ (s) + 2 H₂O (l) → 2 NaOH (aq) + O₂ (g).
Step 5: Balance the hydrogen (H) atoms. There are 4 H atoms on the reactant side (from 2 H₂O) and 4 H atoms on the product side (from 2 NaOH), so the equation is now balanced.

주요 개념

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Balancing Chemical Equations

Balancing chemical equations is the process of ensuring that the number of atoms for each element is the same on both sides of the equation. This is based on the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction. To balance an equation, coefficients are adjusted in front of the chemical formulas to achieve equal atom counts.
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Balancing Chemical Equations

Oxidation-Reduction Reactions

Oxidation-reduction (redox) reactions involve the transfer of electrons between substances, leading to changes in oxidation states. In the reaction involving sodium peroxide (Na₂O₂) and water (H₂O), sodium peroxide acts as an oxidizing agent, and understanding the oxidation states of sodium, oxygen, and hydrogen is crucial for predicting the products formed during the reaction.
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Oxidation and Reduction Reactions

Products of Sodium Peroxide and Water Reaction

When sodium peroxide reacts with water, it typically produces sodium hydroxide (NaOH) and hydrogen peroxide (H₂O₂). Recognizing the expected products of this reaction is essential for completing and balancing the equation correctly. This knowledge helps in determining the stoichiometry of the reaction and ensuring that the final balanced equation accurately reflects the reactants and products involved.
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Reaction with Water