At 1000 K, ๐พ๐ = 1.85 for the reaction SO2(๐) + 12 O2(๐) โ SO3(๐) (c) What is the value of ๐พ๐ for the reaction in part (b)?
Ch.15 - Chemical Equilibrium

Brown15th EditionChemistry: The Central ScienceISBN: 9780137542970๋น์ ์ด ์ฌ์ฉํ๋ ๊ฒ ์๋๋ผ์?๊ต๊ณผ์ ๋ณ๊ฒฝ
15์ฅ, ๋ฌธ์ 26a
Consider the following equilibrium, for which at ๐พ๐ = 0.0752 at 480ยฐC: 2 Cl2(๐) + 2 H2O(๐) โ 4 HCl(๐) + O2(๐) (a) What is the value of ๐พ๐ for the reaction 4 HCl(๐) + O2(๐) โ 2 Cl2(๐) + 2 H2O(๐)?
๊ฒ์ฆ๋ ๋จ๊ณ๋ณ ์๋ด1

๋น์ทํ ๋ฌธ์ ์ ๋ํ ๊ฒ์ฆ๋ ์์ ๋ต๋ณ:
์ด ์์ ํด๋ฒ์ ์ ๋ฌธ์ ์ ๋์์ด ๋๋ค๊ณ ํํฐ๋ค์ด ์ถ์ฒํ ๊ฒ์
๋๋ค.
์์ ๊ธธ์ด:
1m์ฃผ์ ๊ฐ๋
์ง๋ฌธ์ ์ฌ๋ฐ๋ฅด๊ฒ ๋ตํ๊ธฐ ์ํด ๋ฐ๋์ ์ดํดํด์ผ ํ๋ ํต์ฌ ๊ฐ๋
๋ค์ ๋ค์๊ณผ ๊ฐ์ต๋๋ค.
Equilibrium Constant (Kp)
The equilibrium constant, Kp, is a numerical value that expresses the ratio of the concentrations of products to reactants at equilibrium for a given reaction at a specific temperature. It is calculated using the partial pressures of gases involved in the reaction. A Kp value less than 1 indicates that at equilibrium, reactants are favored, while a value greater than 1 indicates that products are favored.
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Equilibrium Constant Expressions
Reversibility of Reactions
Chemical reactions can proceed in both forward and reverse directions, and the equilibrium constant for the reverse reaction is the reciprocal of the forward reaction's equilibrium constant. This means that if you know Kp for a reaction, you can easily find Kp for the reverse reaction by taking the inverse of that value. This principle is crucial for solving equilibrium problems.
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Reversible Changes in Matter
Stoichiometry in Equilibrium
Stoichiometry refers to the quantitative relationship between reactants and products in a chemical reaction, as represented by the balanced equation. In equilibrium expressions, the coefficients of the balanced equation become the exponents in the Kp expression. Understanding stoichiometry is essential for accurately calculating equilibrium constants and predicting the direction of the reaction.
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Stoichiometry Concept
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๊ต๊ณผ์ ์ง๋ฌธ
Consider the equilibrium N2(๐) + O2(๐) + Br2(๐) โ 2 NOBr(๐) Calculate the equilibrium constant ๐พ๐ for this reaction, given the following information at 298 K:
2 NO(๐) + Br2(๐) โ 2 NOBr(๐) ๐พ๐ = 2.02
NO(๐) โ N2(๐) + O2(๐) ๐พ๐ = 2.1ร1030
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๊ต๊ณผ์ ์ง๋ฌธ
Consider the following equilibrium: 2 H2(g) + S2(g) โ 2 H2S(g) Kc = 1.08 ร 107 at 700ยฐC (c) Calculate the value of ๐พ๐ if you rewrote the equation H2(g) + 1/2 S2(g) โ H2S(g)
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๊ต๊ณผ์ ์ง๋ฌธ
The following equilibria were attained at 823 K:
CoO(s) + H2(g) โ Co(s) + H2O(g) Kc = 67
CoO(s) + CO(g) โ Co(s) + CO2(g) Kc = 490
Based on these equilibria, calculate the value of ๐พ๐ for H2(๐)+ CO2(๐) โ CO(๐) + H2O(๐) at 823 K.
