An element X reacts with oxygen to form XO₂ and with chlorine to form XCl₄. XO₂ is a white solid that melts at high temperatures (above 1000 °C). Under usual conditions, XCl₄ is a colorless liquid with a boiling point of 58 °C. (a) XCl₄ reacts with water to form XO₂ and another product. What is the likely identity of the other product?

검증된 단계별 안내

Identify the reaction between XCl4 and water. The given information states that XO2 and another product are formed.

Write the chemical equation for the reaction of XCl4 with water. Since XO2 is one of the products and XCl4 contains chlorine, hypothesize that the other product involves chlorine.

Consider the common reactions of chlorine in compounds when they react with water. Typically, chlorine can form hydrochloric acid (HCl).

Propose a balanced chemical equation: XCl4 + H2O → XO2 + 4 HCl. This equation suggests that hydrochloric acid (HCl) is the other product formed.

Verify the stoichiometry of the proposed reaction to ensure mass and charge are balanced, confirming that all atoms on the reactants side are accounted for in the products.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Chemical Reactions

Chemical reactions involve the transformation of reactants into products through the breaking and forming of chemical bonds. In this case, the reaction of XCl4 with water illustrates a hydrolysis reaction, where water reacts with a compound to produce new substances, including an oxide and an acid or another product.

Oxides and Halides

Oxides are compounds formed by the reaction of an element with oxygen, while halides are compounds formed with halogens like chlorine. The question indicates that X forms XO2 (an oxide) and XCl4 (a halide), which suggests that X is likely a non-metal that can form stable compounds with both oxygen and chlorine.

Acid-Base Reactions

Acid-base reactions involve the transfer of protons (H+) between reactants. In the context of the reaction between XCl4 and water, the likely other product is an acid formed from the chlorine component, such as hydrochloric acid (HCl), indicating that XCl4 acts as a Lewis acid in this reaction.