A 0.944 M solution of glucose, C₆H₁₂O₆, in water has a density of 1.0624 g/mL at 20 °C. What is the concentration of this solution in the following units? (b) Mass percent

검증된 단계별 안내

Step 1: Understand the concept of mass percent. Mass percent is a way of expressing the concentration of a solution, defined as the mass of the solute divided by the total mass of the solution, multiplied by 100%. The formula is:

\frac{mass (solute)}{mass (solution)} \times 100 %

Step 2: Calculate the mass of glucose in 1 liter of solution. Use the molarity of the solution, which is 0.944 M, meaning there are 0.944 moles of glucose per liter of solution. Find the molar mass of glucose, C6H12O6, by adding the atomic masses of its constituent atoms:

6 \times 12.01 + 12 \times 1.01 + 6 \times 16.00

. Multiply the molar mass by the number of moles to find the mass of glucose.

Step 3: Calculate the total mass of the solution. Use the density of the solution, which is 1.0624 g/mL, to find the mass of 1 liter (1000 mL) of solution. Multiply the density by the volume:

1.0624 \times 1000

Step 4: Substitute the values into the mass percent formula. Use the mass of glucose calculated in Step 2 and the total mass of the solution from Step 3. Plug these values into the mass percent formula:

\frac{mass (glucose)}{mass (solution)} \times 100 %

Step 5: Interpret the result. The mass percent will give you the concentration of glucose in the solution as a percentage, indicating how much of the solution's mass is due to glucose.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Molarity

Molarity (M) is a measure of concentration defined as the number of moles of solute per liter of solution. It is commonly used in chemistry to express the concentration of a solution. In this case, the 0.944 M solution of glucose indicates that there are 0.944 moles of glucose dissolved in every liter of the solution.

Mass Percent

Mass percent is a way to express the concentration of a component in a mixture, calculated as the mass of the solute divided by the total mass of the solution, multiplied by 100. This unit is useful for understanding the composition of solutions in terms of mass rather than volume, which can be important for reactions and properties that depend on mass.

Density

Density is defined as mass per unit volume and is an important property of substances. In this context, the density of the glucose solution (1.0624 g/mL) allows us to convert between volume and mass, which is essential for calculating mass percent. Knowing the density helps determine the total mass of the solution when the volume is known.

A 0.944 M solution of glucose, C6H12O6, in water has a density of 1.0624 g/mL at 20 °C. What is the concentration of this solution in the following units? (b) Mass percent