Use the given molar solubilities in pure water to calculate K sp for each compound. b. PbF 2 ; molar solubility = 5.63⨉10 -3 M c. MgF 2 ; molar solubility = 2.65⨉10 -4 M

Identify the dissolution equation for the compound. For PbF_{2}, the dissolution equation is: PbF_{2}(s) ⇌ $$Pb^{2+}(aq$$) + $$2F^{-}(aq).. $$Write the expression for the solubility product constant (K_{sp}) based on the dissolution equation. For PbF_{2}, K_{sp} = [$$Pb^{2+}$$][$$F^{-}$$]^2.. Substitute the molar solubility into the K_{sp} expression. Given the molar solubility of PbF_{2} is 5.63⨉$$10^{-3} M$$, [$$Pb^{2+}$$] = 5.63⨉$$10^{-3} M $$and [$$F^{-}$$] = 2(5.63⨉$$10^{-3}) M.. $$Calculate the concentration of $$F^{-} by $$multiplying the molar solubility of PbF_{2} by 2, as there are two fluoride ions for every formula unit of PbF_{2} that dissolves.. Substitute these concentrations back into the K_{sp} expression and simplify to find the K_{sp} value for PbF_{2}.

Use the given molar solubilities in pure water to calculate Ksp for each compound. b. PbF2; molar solubility = 5.63⨉10-3 M c. MgF2; molar solubility = 2.65⨉10-4 M

Identify the dissolution equation for the compound. For PbF_{2}, the dissolution equation is: PbF_{2}(s) ⇌ $$Pb^{2+}(aq$$) + $$2F^{-}(aq). $$Write the expression for the solubility product constant (K_{sp}) based on the dissolution equation. For PbF_{2}, K_{sp} = [$$Pb^{2+}$$][$$F^{-}$$]^2. Substitute the molar solubility into the K_{sp} expression. Given the molar solubility of PbF_{2} is 5.63⨉$$10^{-3} M$$, [$$Pb^{2+}$$] = 5.63⨉$$10^{-3} M $$and [$$F^{-}$$] = 2(5.63⨉$$10^{-3}) M. $$Calculate the concentration of $$F^{-} by $$multiplying the molar solubility of PbF_{2} by 2, as there are two fluoride ions for every formula unit of PbF_{2} that dissolves. Substitute these concentrations back into the K_{sp} expression and simplify to find the K_{sp} value for PbF_{2}.

Ch.17 - Aqueous Ionic Equilibrium

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Ch.17 - Aqueous Ionic Equilibrium

문제 89b,c

17장, 문제 89b,c

Use the given molar solubilities in pure water to calculate K_sp for each compound. b. PbF₂; molar solubility = 5.63⨉10^-3 M c. MgF₂; molar solubility = 2.65⨉10^-4 M

검증된 단계별 안내

Identify the dissolution equation for the compound. For PbF₂, the dissolution equation is: PbF₂(s) ⇌ Pb²⁺(aq) + 2F^-(aq).

Write the expression for the solubility product constant (K_sp) based on the dissolution equation. For PbF₂, K_sp = [Pb²⁺][F^-]^2.

Substitute the molar solubility into the K_sp expression. Given the molar solubility of PbF₂ is 5.63⨉10^-3 M, [Pb²⁺] = 5.63⨉10^-3 M and [F^-] = 2(5.63⨉10^-3) M.

Calculate the concentration of F^- by multiplying the molar solubility of PbF₂ by 2, as there are two fluoride ions for every formula unit of PbF₂ that dissolves.

Substitute these concentrations back into the K_sp expression and simplify to find the K_sp value for PbF₂.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Molar Solubility

Molar solubility is the number of moles of a solute that can dissolve in one liter of solution at a given temperature. It is a crucial measure in determining how much of a compound can be dissolved in water, which directly influences the calculation of the solubility product constant (Ksp). In this case, the molar solubility of PbF2 is given as 5.63 × 10^-3 M.

Solubility Product Constant (Ksp)

The solubility product constant (Ksp) is an equilibrium constant that reflects the extent to which a sparingly soluble ionic compound dissolves in water. It is calculated from the concentrations of the ions in a saturated solution at equilibrium. For PbF2, Ksp can be derived from its dissociation into Pb²⁺ and F⁻ ions, using the molar solubility to express their concentrations.

Dissociation of Ionic Compounds

Dissociation refers to the process by which an ionic compound separates into its constituent ions when dissolved in water. For PbF2, the dissociation can be represented as PbF2(s) ⇌ Pb²⁺(aq) + 2F⁻(aq). Understanding this process is essential for calculating Ksp, as it allows us to relate the molar solubility to the concentrations of the ions produced in solution.