Bismuth-210 is a beta emitter with a half-life of 5.0 days. If a sample contains 1.2 g of Bi-210 (atomic mass = 209.984105 amu), how many beta emissions occur in 13.5 days? If a person’s body intercepts 5.5% of those emissions, what amount of radiation (in Ci) is the person exposed to?

Half-life is the time required for half of the radioactive nuclei in a sample to decay. For Bismuth-210, with a half-life of 5.0 days, this means that after 5 days, half of the original amount will have decayed. Understanding half-life is crucial for calculating the remaining quantity of a radioactive substance over time and predicting the number of decay events that will occur.

Beta decay is a type of radioactive decay in which a beta particle (an electron or positron) is emitted from an atomic nucleus. In the case of Bismuth-210, it undergoes beta decay, transforming into a different element while releasing energy. This process is essential for determining the number of emissions that occur over a specified time period, as each decay event corresponds to one beta emission.

Radioactivity refers to the process by which unstable atomic nuclei lose energy by emitting radiation. The exposure to radiation can be quantified in curies (Ci), a unit that measures the activity of a radioactive source. To calculate the exposure a person receives from beta emissions, one must consider the total emissions and the percentage intercepted, allowing for an assessment of potential health risks associated with radiation exposure.