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Ch.4 - Chemical Quantities & Aqueous Reactions
Tro - Chemistry: A Molecular Approach 4th Edition
Tro4th EditionChemistry: A Molecular ApproachISBN: 9780134112831당신이 사용하는 게 아니라요?교과서 변경
4장, 문제 112

Predict the products and write a balanced molecular equation for each reaction. If no reaction occurs, write “NO REACTION.” a. H2SO4(aq) + HNO3(aq) b. aqueous strontium sulfide and aqueous copper(II) sulfate.

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1
insert step 1> Identify the type of reaction for each given pair of reactants.
insert step 2> For part (a), recognize that both H2SO4 and HNO3 are strong acids and typically do not react with each other in aqueous solution, so write 'NO REACTION.'
insert step 3> For part (b), recognize that this is a double displacement reaction involving aqueous strontium sulfide (SrS) and aqueous copper(II) sulfate (CuSO4).
insert step 4> Write the potential products of the double displacement reaction: strontium sulfate (SrSO4) and copper(II) sulfide (CuS).
insert step 5> Balance the molecular equation: SrS(aq) + CuSO4(aq) -> SrSO4(s) + CuS(s).

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Acid-Base Reactions

Acid-base reactions involve the transfer of protons (H+) between reactants. In this context, sulfuric acid (H2SO4) and nitric acid (HNO3) are both strong acids that can donate protons. Understanding how these acids interact is crucial for predicting the products of their reaction, which may involve the formation of new compounds or ions.
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가이드 코스
01:09
Acid-Base Reaction

Double Displacement Reactions

Double displacement reactions occur when the anions and cations of two different compounds exchange places, forming two new compounds. In the case of strontium sulfide and copper(II) sulfate, this type of reaction can lead to the formation of strontium sulfate and copper(II) sulfide. Recognizing the potential for precipitate formation is essential for determining the products of such reactions.
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가이드 코스
01:11
Single Displacement Reactions

Balancing Chemical Equations

Balancing chemical equations is the process of ensuring that the number of atoms for each element is the same on both sides of the equation. This is important for accurately representing the conservation of mass in a chemical reaction. A balanced equation provides insight into the stoichiometry of the reaction, allowing for the prediction of product quantities and the identification of reactants.
추천 영상:
가이드 코스
01:32
Balancing Chemical Equations