How many fluorine atoms are present in 5.85 g of C₂F₄?

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Determine the molar mass of C2F4. Carbon (C) has an atomic mass of approximately 12.01 g/mol and fluorine (F) has an atomic mass of approximately 19.00 g/mol. The molar mass of C2F4 is calculated as: (2 \(\times\) 12.01) + (4 \(\times\) 19.00) g/mol.

Calculate the number of moles of C2F4 in 5.85 g using the formula: \(\text{moles}\) = \(\frac{\text{mass}\)}{\(\text{molar mass}\)}.

Each molecule of C2F4 contains 4 fluorine atoms. To find the total number of fluorine atoms, multiply the number of moles of C2F4 by Avogadro's number (6.022 \(\times\) 10^{23} \(\text{ molecules/mol}\)) and then by 4 (since each molecule has 4 fluorine atoms).

The calculation for the total number of fluorine atoms is: \(\text{total fluorine atoms}\) = \(\text{moles of C2F4}\) \(\times\) 6.022 \(\times\) 10^{23} \(\times\) 4.

This will give you the total number of fluorine atoms present in 5.85 g of C2F4.

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주요 개념

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Molar Mass

Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). For C2F4, the molar mass is calculated by summing the atomic masses of its constituent elements: carbon (C) and fluorine (F). This value is essential for converting between grams and moles, which is necessary to determine the number of atoms in a given mass of the compound.

Avogadro's Number

Avogadro's number, approximately 6.022 x 10^23, is the number of particles (atoms, molecules, etc.) in one mole of a substance. This constant allows chemists to relate the macroscopic scale of substances (grams) to the microscopic scale (individual atoms or molecules). In this question, it will be used to find the number of fluorine atoms from the moles of C2F4.

Stoichiometry

Stoichiometry is the calculation of reactants and products in chemical reactions based on the conservation of mass. In this context, it involves determining the ratio of fluorine atoms to C2F4 molecules. Since each molecule of C2F4 contains four fluorine atoms, stoichiometry will help in calculating the total number of fluorine atoms present in the given mass of the compound.

How many fluorine atoms are present in 5.85 g of C2F4?