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Ch.4 - Chemical Reactions and Chemical Quantities
Tro - Chemistry: A Molecular Approach 5th Edition
Tro5th EditionChemistry: A Molecular ApproachISBN: 9780134874371당신이 사용하는 게 아니라요?교과서 변경
4장, 문제 31

Hydrobromic acid dissolves solid iron according to the reaction:
Fe(s) + 2 HBr(aq) → FeBr2(aq) + H2(g)
What mass of HBr (in g) do you need to dissolve a 3.2-g pure iron bar on a padlock? What mass of H2 would the complete reaction of the iron bar produce?

검증된 단계별 안내
1
Determine the molar mass of iron (Fe) and hydrobromic acid (HBr).
Calculate the number of moles of iron in the 3.2-g iron bar using its molar mass.
Use the stoichiometry of the balanced chemical equation to find the moles of HBr needed. The equation shows that 1 mole of Fe reacts with 2 moles of HBr.
Convert the moles of HBr to grams using the molar mass of HBr.
Calculate the moles of H2 produced using the stoichiometry of the reaction, where 1 mole of Fe produces 1 mole of H2, and then convert this to grams using the molar mass of H2.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
2m
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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Stoichiometry

Stoichiometry is the calculation of reactants and products in chemical reactions based on the balanced chemical equation. It allows us to determine the relationships between the amounts of substances involved in a reaction, using mole ratios derived from the coefficients in the balanced equation. In this case, it helps us find the mass of HBr needed to react with a given mass of iron and the mass of hydrogen gas produced.
추천 영상:
가이드 코스
01:16
Stoichiometry Concept

Molar Mass

Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). It is essential for converting between the mass of a substance and the number of moles, which is necessary for stoichiometric calculations. For this problem, knowing the molar masses of iron (Fe) and hydrobromic acid (HBr) will allow us to calculate the required mass of HBr and the mass of hydrogen gas produced.
추천 영상:
가이드 코스
02:11
Molar Mass Concept

Gas Laws

Gas laws describe the behavior of gases under various conditions of temperature and pressure. In this context, while the production of hydrogen gas (H2) is a result of the reaction, understanding gas laws can help predict how the gas behaves after formation. Although not directly required for mass calculations, it provides insight into the properties of the gas produced in the reaction.
추천 영상:
가이드 코스
01:43
Combined Gas Law
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교과서 질문

Consider the balanced equation:

SiO2(s) + 3 C(s) → SiC(s) + 2 CO(g)

Complete the table showing the appropriate number of moles of reactants and products. If the number of moles of a reactant is provided, fill in the required amount of the other reactant, as well as the moles of each product that forms. If the number of moles of a product is provided, fill in the required amount of each reactant to make that amount of product, as well as the amount of the other product that forms.

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교과서 질문

Hydrobromic acid dissolves solid iron according to the reaction:

Fe(s) + 2 HBr(aq) → FeBr2(aq) + H2(g)

What mass of HBr (in g) do you need to dissolve a 3.2-g pure iron bar on a padlock?

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교과서 질문

For each of the reactions, calculate the mass (in grams) of the product that forms when 15.39 g of the underlined reactant completely reacts. Assume that there is more than enough of the other reactant.

a. 2 K(s) + Cl2(g) → 2 KCl(s)

b. 2 K(s) + Br2(l) → 2 KBr(s)

c. 4 Cr(s) + 3 O2(g) → 2 Cr2O3(s)

d. 2 Sr(s) + O2(g) → 2 SrO(s)

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교과서 질문

Consider the balanced equation:

SiO2(s) + 3 C(s) → SiC(s) + 2 CO(g)

Complete the table showing the appropriate number of moles of reactants and products. If the number of moles of a reactant is provided, fill in the required amount of the other reactant, as well as the moles of each product that forms. If the number of moles of a product is provided, fill in the required amount of each reactant to make that amount of product, as well as the amount of the other product that forms.

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Calculate how many moles of NH3 form when each quantity of reactant completely reacts. 3 N2H4(l) → 4 NH3(g) + N2(g) c. 65.3 g N2H4

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