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Ch.5 - Introduction to Solutions and Aqueous Solutions
Tro - Chemistry: A Molecular Approach 5th Edition
Tro5th EditionChemistry: A Molecular ApproachISBN: 9780134874371당신이 사용하는 게 아니라요?교과서 변경
5장, 문제 24c

what is the molarity of Cl- in each solution? c. 0.100 M AlCl3

검증된 단계별 안내
1
Step 1: Understand the dissociation of AlCl3 in water. AlCl3 dissociates into one Al3+ ion and three Cl- ions. The balanced chemical equation is: AlCl3 → Al3+ + 3Cl-.
Step 2: Identify the initial concentration of AlCl3. The problem states that the concentration of AlCl3 is 0.100 M.
Step 3: Determine the stoichiometry of the dissociation. From the balanced equation, for every 1 mole of AlCl3 that dissociates, 3 moles of Cl- are produced.
Step 4: Calculate the concentration of Cl- ions. Multiply the initial concentration of AlCl3 by the stoichiometric coefficient of Cl- from the balanced equation: 0.100 M AlCl3 × 3 = concentration of Cl-.
Step 5: Conclude with the molarity of Cl- ions. The molarity of Cl- in the solution is three times the molarity of AlCl3 due to the 1:3 ratio in the dissociation equation.

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주요 개념

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Molarity

Molarity is a measure of concentration defined as the number of moles of solute per liter of solution. It is expressed in units of moles per liter (M). Understanding molarity is essential for calculating the concentration of ions in a solution, as it allows for the conversion between moles of solute and the volume of the solution.
추천 영상:

Dissociation of Ionic Compounds

Ionic compounds, such as aluminum chloride (AlCl3), dissociate into their constituent ions when dissolved in water. For AlCl3, it dissociates into one aluminum ion (Al^3+) and three chloride ions (Cl^-). This dissociation is crucial for determining the concentration of specific ions in solution, as the total number of ions produced affects the overall molarity.
추천 영상:
가이드 코스
02:11
Ionic Compounds Naming

Stoichiometry of Dissociation

Stoichiometry involves the quantitative relationship between reactants and products in a chemical reaction. In the case of AlCl3, the stoichiometry indicates that one mole of AlCl3 produces three moles of Cl^-. Therefore, to find the molarity of Cl^- in a 0.100 M AlCl3 solution, one must multiply the molarity of AlCl3 by the stoichiometric coefficient of Cl^- from the dissociation equation.
추천 영상:
가이드 코스
01:16
Stoichiometry Concept