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Ch.4 - Chemical Reactions and Chemical Quantities
Tro - Chemistry: A Molecular Approach 6th Edition
Tro6th EditionChemistry: A Molecular ApproachISBN: 9780137832217당신이 사용하는 게 아니라요?교과서 변경
4장, 문제 30

Consider the unbalanced equation for the neutralization of acetic acid: HC2H3O2(aq) + Ba(OH)2(aq) → H2O(l) + Ba(C2H3O2)2(aq) Balance the equation and determine how many moles of Ba(OH)2 are required to completely neutralize 1.22 mol of HC2H3O2.

검증된 단계별 안내
1
Step 1: Write the unbalanced chemical equation: \[ \text{HC}_2\text{H}_3\text{O}_2(\text{aq}) + \text{Ba(OH)}_2(\text{aq}) \rightarrow \text{H}_2\text{O}(\text{l}) + \text{Ba(C}_2\text{H}_3\text{O}_2)_2(\text{aq}) \]
Step 2: Balance the equation by ensuring the number of atoms of each element is the same on both sides. Start by balancing the acetate ions (C₂H₃O₂⁻) and then balance the water molecules.
Step 3: The balanced equation should look like this: \[ 2\text{HC}_2\text{H}_3\text{O}_2(\text{aq}) + \text{Ba(OH)}_2(\text{aq}) \rightarrow 2\text{H}_2\text{O}(\text{l}) + \text{Ba(C}_2\text{H}_3\text{O}_2)_2(\text{aq}) \]
Step 4: Use the stoichiometry of the balanced equation to determine the mole ratio between HC₂H₃O₂ and Ba(OH)₂. From the balanced equation, 2 moles of HC₂H₃O₂ react with 1 mole of Ba(OH)₂.
Step 5: Calculate the moles of Ba(OH)₂ needed to neutralize 1.22 moles of HC₂H₃O₂ using the mole ratio: \[ \text{Moles of Ba(OH)}_2 = \frac{1.22 \text{ moles HC}_2\text{H}_3\text{O}_2}{2} \]

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
2m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Neutralization Reaction

A neutralization reaction occurs when an acid reacts with a base to produce water and a salt. In this case, acetic acid (HC2H3O2) reacts with barium hydroxide (Ba(OH)2) to form water (H2O) and barium acetate (Ba(C2H3O2)2). Understanding this concept is crucial for balancing the chemical equation and determining the stoichiometric relationships between the reactants and products.
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가이드 코스
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Lewis Dot Structures: Neutral Compounds

Balancing Chemical Equations

Balancing chemical equations involves ensuring that the number of atoms for each element is the same on both sides of the equation. This is achieved by adjusting the coefficients of the reactants and products. For the given reaction, balancing is essential to accurately reflect the conservation of mass and to determine the correct mole ratios needed for calculations.
추천 영상:
가이드 코스
01:32
Balancing Chemical Equations

Stoichiometry

Stoichiometry is the quantitative relationship between reactants and products in a chemical reaction. It allows us to calculate the amount of one substance needed to react with a given amount of another. In this question, stoichiometry will help determine how many moles of Ba(OH)2 are required to neutralize 1.22 moles of acetic acid based on the balanced equation.
추천 영상:
가이드 코스
01:16
Stoichiometry Concept