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Introduction to Logarithmic Functions quiz
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What is a logarithm in relation to an exponential function?
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What is a logarithm in relation to an exponential function?
A logarithm is the exponent that a base must be raised to in order to equal a particular number; it is the inverse of an exponential function.
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Introduction to Logarithmic Functions definitions
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이 집합의 용어 (15)
하이드의 정의
What is a logarithm in relation to an exponential function?
A logarithm is the exponent that a base must be raised to in order to equal a particular number; it is the inverse of an exponential function.
How do you write the exponential equation 2^y = 10 in logarithmic form?
You write it as y = log base 2 of 10, or y = log₂(10).
What does the notation log_b(x) mean?
It means the exponent y such that b^y = x; b is the base and x is the argument.
How are exponential and logarithmic forms related?
They are inverses: y = log_b(x) is equivalent to x = b^y.
What is the base in the logarithmic expression log_5(x)?
The base is 5.
How do you convert the logarithmic equation log_3(81) = 4 to exponential form?
You write it as 3^4 = 81.
What is the inverse function of f(x) = 5^x?
The inverse is f⁻¹(x) = log base 5 of x, or f⁻¹(x) = log₅(x).
What is the value of log_2(2^3)?
It is 3, because the log and exponential with the same base cancel, leaving the exponent.
What is the value of log_b(b) for any base b?
It is always 1, because b^1 = b.
What is the value of log_b(1) for any base b?
It is always 0, because any base raised to the power of 0 equals 1.
How can you evaluate log_4(16) without a calculator?
Rewrite 16 as 4^2, so log_4(4^2) = 2.
How do you evaluate log_5(1/5) using exponent rules?
Rewrite 1/5 as 5^(-1), so log_5(5^(-1)) = -1.
How do you rewrite the cube root of 4 as an exponent?
The cube root of 4 is 4^(1/3).
What is log_4(∛4) equal to?
It is 1/3, because log_4(4^(1/3)) = 1/3.
What two elements should you focus on when converting between exponential and logarithmic forms?
Focus on the base and the exponent, as they determine the structure of both forms.