The water level in a graduated cylinder initially at 215 mL rises...

Question

The water level in a graduated cylinder initially at 215 mL rises to 285 mL after a piece of lead is submerged. What is the mass, in grams, of the lead(see TABLE2.8)? (2.7)

Accepted Answer

Welcome back everyone. A piece of bismuth metal is submerged in a graduated cylinder containing 65.4 mL of water. The water level in the graduated cylinder rises to 73.5 mL. After the metal is added, calculate the mass in grams of the bismuth metal. The density of bismuth is 9.79 g per milliliter. So let's imagine our graduated cylinder which will draw a sketch of we're told that we have an initial water level V I of our water Equal to 64 or sorry, 65.4 ml. Now, we can imagine our piece of business metal represented by the chemical symbol B I which is then added to our graduated cylinder and displaces our water to a higher water level which we're told has a volume V F of water. So the final Of water equal to 73.5 ml. So let's recall that to find the volume of our business metal, this would just be equal to the volume of our water displacement, which ultimately means we take the difference between our final volume of our water subtracted from the initial volume of our water And because we know those two terms, we can just take the difference directly. So we have our final volume of water in the cylinder as 73.5 mL subtracted from the initial volume of the water in the graduated cylinder as 65. mL. And from this difference, we find our volume of water displacement equal to 8. mL, which is also our volume of bismuth metal. Next, let's recall our formula which relates density represented by row equal to mass in the numerator divided by volume. And so we want to solve for the mass of bismuth as our final answer. So we're going to multiply both sides by volume. And what we'll find is that it cancels out on the right and we would find that mass is equal to density times volume. And so we would plug in our given density of bismuth from the prompt as 9.79 g per milliliter. And this is multiplied by our volume, which we calculated for bismuth as 8.10 ml. Notice that we have milliliters in the numerator from our volume and in the denominator from our density, so that those two units will cancel out leaving us with grams as our final unit for mass, which is what we want. And we're going to find that our mass of bismuth Is equal to a value of 79.3 g. And this would be our final answer as our mass of business metal, which corresponds to choice c in the multiple choice 79. g. I hope this made sense. And let us know if you have any questions.

The water level in a graduated cylinder initially at 215 mL rises to 285 mL after a piece of lead is submerged. What is the mass, in grams, of the lead(see TABLE2.8)? (2.7)

주요 개념

Density

Displacement Method

Graduated Cylinder

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