Given the following molecular orbital diagram for diatomic molecules, which of the following species is expected to be the most stable? (Assume the diagram is for second-period homonuclear diatomics and consider bond order only.)
A
B
C
D
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1
Identify the molecular orbital (MO) electron configuration for each diatomic molecule (B₂, C₂, N₂, O₂) using the given MO diagram for second-period homonuclear diatomics. Remember that the order of orbitals for B₂, C₂, and N₂ is different from O₂ due to the energy level crossover between \( \sigma_{2p_z} \) and \( \pi_{2p_x}, \pi_{2p_y} \) orbitals.
Count the total number of valence electrons for each molecule: B₂ has 10, C₂ has 12, N₂ has 14, and O₂ has 16 valence electrons.
Fill the molecular orbitals with the valence electrons according to the Aufbau principle, Hund's rule, and Pauli exclusion principle, making sure to place electrons in bonding and antibonding orbitals correctly.
Calculate the bond order for each molecule using the formula:
\[ \text{Bond order} = \frac{(\text{number of electrons in bonding MOs}) - (\text{number of electrons in antibonding MOs})}{2} \]
Higher bond order indicates a stronger and more stable bond.
Compare the bond orders of B₂, C₂, N₂, and O₂. The molecule with the highest bond order is expected to be the most stable species.