Which of the following best represents the correct Lewis structure for (thionitrosyl hydride)?
A
is single-bonded to , is single-bonded to , and both and have two lone pairs
B
is double-bonded to , is single-bonded to , and has no lone pairs
C
is single-bonded to , is double-bonded to , and has two lone pairs
D
is single-bonded to , is double-bonded to , and has one lone pair
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검증된 단계별 안내
1
Step 1: Determine the total number of valence electrons for the molecule HNS. Hydrogen (H) has 1 valence electron, nitrogen (N) has 5, and sulfur (S) has 6, so total valence electrons = 1 + 5 + 6 = 12 electrons.
Step 2: Consider the connectivity given: hydrogen is bonded to nitrogen, and nitrogen is bonded to sulfur. Start by drawing single bonds between H-N and N-S, which uses 4 electrons (2 electrons per bond).
Step 3: Distribute the remaining electrons to satisfy the octet rule for nitrogen and sulfur. Hydrogen only needs 2 electrons (already satisfied by its single bond). Assign lone pairs to nitrogen and sulfur to complete their octets, keeping in mind nitrogen typically forms three bonds and has one lone pair, while sulfur can expand its octet if needed.
Step 4: Evaluate the possibility of multiple bonds to satisfy the octet rule and minimize formal charges. Since nitrogen has 5 valence electrons and sulfur has 6, consider forming a double bond between nitrogen and sulfur to reduce formal charges and complete octets.
Step 5: Confirm the final Lewis structure by checking that all atoms have complete octets (except hydrogen), the total number of electrons equals 12, and formal charges are minimized. This leads to hydrogen single-bonded to nitrogen, nitrogen double-bonded to sulfur, and nitrogen having one lone pair.