Which of the following is the correct final product when reacts with followed by acidic workup in a Grignard reaction?
A
B
C
D
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1
Identify the reactants: PhMgBr is a Grignard reagent (phenylmagnesium bromide), and acetone is a ketone with the structure (CH3)2C=O.
Recall the general mechanism of a Grignard reaction with a ketone: the nucleophilic carbon in the Grignard reagent attacks the electrophilic carbonyl carbon of the ketone, breaking the C=O double bond and forming a tetrahedral alkoxide intermediate.
Write the nucleophilic attack step: the phenyl group (Ph-) from PhMgBr attacks the carbonyl carbon of acetone, resulting in an alkoxide intermediate with the structure Ph-C(O^-)-Me-Me.
Consider the acidic workup step: protonation of the alkoxide intermediate by acid (H3O+) converts the alkoxide into an alcohol, yielding a tertiary alcohol with the structure Ph-C(OH)-Me-Me.
Conclude that the final product is a tertiary alcohol where the phenyl group is attached to the former carbonyl carbon, now bearing an OH group, and two methyl groups remain attached to that carbon.