When compound A, 2-butanol (), is dehydrated with concentrated , what is the major alkene product?
A
cis-2-butene (, cis isomer)
B
1-butene ()
C
2-butene ()
D
No alkene is formed
0 댓글
검증된 단계별 안내
1
Identify the structure of 2-butanol: it is a four-carbon chain with an -OH group on the second carbon, specifically CH\3-CH(OH)-CH\2-CH\3.
Understand that dehydration of an alcohol with concentrated H\2SO\4 involves protonation of the -OH group to form a good leaving group (water), followed by elimination to form a double bond (alkene).
Determine the possible alkenes formed by removing a proton from the beta carbons adjacent to the carbon bearing the -OH group. For 2-butanol, the beta carbons are C1 and C3, leading to possible alkenes: 1-butene (double bond between C1 and C2) and 2-butene (double bond between C2 and C3).
Apply Zaitsev's rule, which states that the more substituted alkene (the one with more alkyl groups attached to the double-bonded carbons) is the major product because it is more stable. Compare the substitution of 1-butene and 2-butene.
Conclude that the major alkene product is 2-butene due to its greater substitution and stability compared to 1-butene.