In a molecule of cumulene with the formula , how many sigma () and pi () bonds are present?
A
sigma and pi bonds
B
sigma and pi bonds
C
sigma and pi bonds
D
sigma and pi bonds
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검증된 단계별 안내
1
Step 1: Understand the structure of cumulene C4H4. Cumulenes are compounds with consecutive double bonds between carbon atoms. For C4H4, the carbon atoms are connected in a chain with double bonds between them, typically represented as C=C=C=C, and each terminal carbon is bonded to one hydrogen atom.
Step 2: Count the sigma (\(\sigma\)) bonds. Each single bond consists of one sigma bond. In cumulene, each carbon-carbon double bond consists of one sigma and one pi bond. There are three carbon-carbon double bonds, so there are 3 sigma bonds from these. Additionally, each carbon is bonded to hydrogens with single bonds, contributing more sigma bonds. Sum all sigma bonds from C-C and C-H bonds.
Step 3: Count the pi (\(\pi\)) bonds. Each double bond has one pi bond. Since there are three consecutive double bonds between the four carbons, there are 3 pi bonds from these. However, in cumulenes, the central carbons have two double bonds each, so the total number of pi bonds is the number of double bonds, which is 3.
Step 4: Verify the total number of bonds. The total number of bonds in the molecule is the sum of all sigma and pi bonds. Remember that each bond between atoms is either a sigma or a pi bond, and double bonds count as one sigma plus one pi bond.
Step 5: Summarize the counts. Add the sigma bonds from all C-C and C-H single bonds and the pi bonds from the double bonds to get the final count of sigma and pi bonds in the molecule.